Same Tree

Same Tree


Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.




# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def isSameTree(self, p, q):
:type p: TreeNode
:type q: TreeNode
:rtype: bool
if p is None and q is None:
return True
if p is None and q is not None or p is not None and q is None:
return False
if p.val == q.val and self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right):
return True
return False



public class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if (p == null && q == null) return true;
if ((p == null && q != null) || (p != null && q == null)) return false;
if (p.val != q.val) return false;
return isSameTree(p.left,q.left) && isSameTree(p.right,q.right);


func isSameTree(p *NodeTree, q *NodeTree) bool {
if p == nil && q == nil {
return true
if (p != nil && q == nil) || (p == nil && q != nil){
return false
if p.Val != q.Val {
return False
return isSameTree(p.Left, q.Left) && isSameTree(p.Right, q.Right)